(k-1)(x^2+kx+1)=0

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Solution for (k-1)(x^2+kx+1)=0 equation: 


Simplifying
(k + -1)(x2 + kx + 1) = 0

Reorder the terms:
(-1 + k)(x2 + kx + 1) = 0

Reorder the terms:
(-1 + k)(1 + kx + x2) = 0

Multiply (-1 + k) * (1 + kx + x2)
(-1(1 + kx + x2) + k(1 + kx + x2)) = 0
((1 * -1 + kx * -1 + x2 * -1) + k(1 + kx + x2)) = 0
((-1 + -1kx + -1x2) + k(1 + kx + x2)) = 0
(-1 + -1kx + -1x2 + (1 * k + kx * k + x2 * k)) = 0

Reorder the terms:
(-1 + -1kx + -1x2 + (1k + kx2 + k2x)) = 0
(-1 + -1kx + -1x2 + (1k + kx2 + k2x)) = 0

Reorder the terms:
(-1 + 1k + -1kx + kx2 + k2x + -1x2) = 0
(-1 + 1k + -1kx + kx2 + k2x + -1x2) = 0

Solving
-1 + 1k + -1kx + kx2 + k2x + -1x2 = 0

Solving for variable 'k'.

The solution to this equation could not be determined.

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